Question

what is the missing particle?

233/92u→4/2he+?

229/90th 229/92u 233/90th

Explanation:

Step1: Calculate the mass number of the missing particle

The mass number of \(^{233}_{92}U\) is \(233\), and the mass number of \(^{4}_{2}He\) is \(4\). Let the mass number of the missing particle be \(A\). According to the conservation of mass number \(A = 233- 4=229\)

Step2: Calculate the atomic number of the missing particle

The atomic number of \(^{233}_{92}U\) is \(92\), and the atomic number of \(^{4}_{2}He\) is \(2\). Let the atomic number of the missing particle be \(Z\). According to the conservation of atomic number \(Z=92 - 2 = 90\)

Step3: Identify the element

The element with atomic number \(90\) is Thorium (\(Th\))

Answer:

\(^{229}_{90}Th\) (the first option \(^{229}_{90}Th\))