Question

1. what is the midpoint m given s(-8, -6) and t(4, 12)?

(-6, -9)
(-1, -4)
(7, 8)
(-2, 3)

Explanation:

Step1: Midpoint formula for x - coordinate

The midpoint formula for two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(M(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})\).
For \(x\) - coordinate: \(x_1=-8,x_2 = 4\), so \(\frac{-8 + 4}{2}=\frac{-4}{2}=-2\).

Step2: Midpoint formula for y - coordinate

For \(y\) - coordinate: \(y_1=-6,y_2 = 12\), so \(\frac{-6+12}{2}=\frac{6}{2}=3\).

Answer:

\((-2,3)\)