what is the measure of $ \angle adc $ in quadrilateral $ abcd $?
$ 45 ^ { \circ } $
$ 65 ^ { \circ } $
$ 115 ^ { \circ } $
$ 135 ^ { \circ } $

Question

Accepted Answer

# Explanation:
## Step1: Recall the property of parallelogram
In a parallelogram, adjacent angles are supplementary. That is, $\angle A+\angle ADC = 180^{\circ}$

## Step2: Solve for $\angle ADC$
Given $\angle A=115^{\circ}$, then $\angle ADC=180^{\circ}-\angle A$
$$
\begin{align*}
\angle ADC&=180 - 115\
&=65^{\circ}
\end{align*}
$$

# Answer:
$65^{\circ}$ (the second option)

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QUESTION IMAGE

Question

Explanation:

Step1: Recall the property of parallelogram

Step2: Solve for \(\angle ADC\)

Answer: