Question

what is the measure of \angle edh?
\\( 10 ^ { \circ } \\)
\\( 40 ^ { \circ } \\)
\\( 50 ^ { \circ } \\)
\\( 90 ^ { \circ } \\)

Explanation:

Step1: Use the property of right - angle

Since \( \angle EDG = 90^{\circ}\), we have \(5x+4x = 90\).

Step2: Solve the equation for \(x\)

Combine like terms: \(9x=90\). Then \(x = 10\) (divide both sides by 9: \(x=\frac{90}{9}\)).

Step3: Find the measure of \(\angle EDH\)

Substitute \(x = 10\) into \(5x\). So \(5x=5\times10 = 50\).

Answer:

\(50^{\circ}\)