Question

1. what is the lewis dot structure for f?

options (lewis dot structures for f)

1. which of these is a correct lewis structure for iodine (i₂)?

options (lewis structures for i₂)

1. what is the lewis dot structure for se?

options (lewis dot structures for se)

1. which of these is a correct lewis structure for dicarbon monoxide (c₂o)?

options (lewis structures for c₂o)

Explanation:

Question 7

Step 1: Determine valence electrons of F

Fluorine (F) is in group 17, so it has 7 valence electrons.

Step 2: Draw Lewis dot structure

A Lewis dot structure for an atom shows the valence electrons as dots around the symbol. F has 7 valence electrons, so we place 7 dots around F. The correct structure should have 3 lone pairs (6 dots) and 1 unpaired dot, or arranged as :F with 3 pairs and 1 single dot? Wait, no, the standard Lewis dot for F is with 7 electrons: 2 in one pair and 5? Wait, no, group 17 has 7 valence electrons. So the correct Lewis dot structure for F is the one with 7 electrons, which is the second option (the one with F and 7 dots: 3 pairs and 1 single, like .F: with three pairs around? Wait, the options: let's see the options. The second option is .F: with three pairs (6 dots) and one single, so total 7. So that's correct.

Step 1: Valence electrons of I

Iodine (I) is in group 17, so 7 valence electrons. For $I_2$, we need to form a covalent bond. Each I has 7 valence electrons, so total valence electrons: 7*2 = 14.

Step 2: Draw Lewis structure

We need to have a single bond between the two I atoms (since they are both nonmetals, covalent bond). Each I will then have 3 lone pairs (6 electrons) and the bond (2 electrons), so total 8 electrons around each I (octet). So the structure should be :$\ddot{\text{I}} - \ddot{\text{I}}\colon$ (with three lone pairs on each I and a single bond). So the second option (the one with :$\ddot{\text{I}} - \ddot{\text{I}}\colon$) is correct.

Step 1: Valence electrons of Se

Selenium (Se) is in group 16, so it has 6 valence electrons.

Step 2: Draw Lewis dot structure

A Lewis dot structure for Se should show 6 valence electrons. So the correct structure is the one with 6 dots around Se. Looking at the options, the fourth option (::Se:) with 6 dots (two pairs and two single dots) is correct.

Answer:

The second option (the one with .$\ddot{\text{F}}\colon$? Wait, no, the options: first is .$\dot{\text{F}}\cdot$, second is .$\ddot{\text{F}}\colon$? Wait, maybe the second option is the correct one with 7 electrons. So the answer is the second option (the one labeled with F and 7 dots, like .F: with three pairs and one single dot, total 7).

Question 8