Question

1. what happens to a springs force if you stretch it more?

Explanation:

Step1: Recall Hooke's Law

Hooke's Law is \(F = -kx\), where \(F\) is the force exerted by the spring, \(k\) is the spring constant (a property of the spring, remains constant for a given spring), and \(x\) is the displacement (stretch or compression) from the spring's equilibrium position.

Step2: Analyze the relationship between \(F\) and \(x\)

Since \(k>0\) (spring constant is positive for a normal spring), when \(x\) (the stretch) increases (i.e., \(|x|\) gets larger), the magnitude of \(F\) (because \(F\) is proportional to \(x\) as \(F = k|x|\) when considering magnitude) increases. The negative sign in \(F=-kx\) just indicates the direction of the force (opposite to the direction of displacement), but when talking about the "force" in terms of its magnitude, we consider \(|F|\).

Answer:

The magnitude of the spring's force increases.