Question

what is the equation of the line that passes through the point (2, - 6) and has a slope of - 3?

Explanation:

Step1: Recall point - slope form

The point - slope form of a line is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope.

Step2: Substitute values

Given $(x_1,y_1)=(2,-6)$ and $m = - 3$. Substitute into the point - slope form: $y-(-6)=-3(x - 2)$.

Step3: Simplify the equation

$y + 6=-3x+6$. Then, subtract 6 from both sides to get $y=-3x$.

Answer:

$y=-3x$