Question

what element has the electron configuration 1s²2s²2p³ nitrogen magnesium oxygen carbon

Explanation:

Step1: Calculate the total number of electrons

The electron configuration is \(1s^{2}2s^{2}2p^{3}\). Add the exponents: \(2 + 2+3=7\) electrons.

Step2: Relate to atomic number

In a neutral atom, the number of electrons equals the atomic number. The element with atomic number \(7\) is nitrogen.

Answer:

A. Nitrogen