Question

what is the electron configuration of the sodium atom after it loses an electron?
a) 1s²2s²2p⁶
b) 1s²2s²2p⁶3s¹
c) 1s²2s²2p⁶3s¹
d) he2s²2p⁵

Explanation:

Step1: Determine the electron configuration of sodium atom

Sodium (\(Na\)) has an atomic number of \(11\). The electron configuration of a neutral sodium atom is \(1s^{2}2s^{2}2p^{6}3s^{1}\).

Step2: Analyze electron loss

When a sodium atom loses an electron, it loses the outermost electron (from the \(3s\) orbital).

Step3: Write the new electron configuration

After losing one electron, the electron configuration becomes \(1s^{2}2s^{2}2p^{6}\).

Answer:

A. \(1s^{2}2s^{2}2p^{6}\)