Question

what is the current through the ammeter of the following circuit?

\\(v = 14.9\text{ v}\\)
\\(r = 112\\ \omega\\)
\\(r_2 = 210\\ \omega\\)
\\(r_3 = 168\\ \omega\\)

• 0.104 a
• 013.8 a
• 0.0726 a
• 0.0373 a

Explanation:

Identify parallel resistors

Using the Series and Parallel Circuits knowledge point

$$
LATEXBLOCK0
$$

Calculate total equivalent resistance

Using the Equivalent Resistance knowledge point

$$
LATEXBLOCK1
$$

Calculate total circuit current

Using the Ohm's Law knowledge point

$$
LATEXBLOCK2
$$

Determine ammeter reading

The ammeter is connected in series with the main branch of the circuit, directly measuring the total current leaving the voltage source before it splits into the parallel branches.

$$ I_{\text{ammeter}} = I_{total} \approx 0.0726\ \text{A} $$

Answer:

• 0.104 A
• 013.8 A
• 0.0726 A (Correct answer)
• 0.0373 A