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what is the completely factored form of \\(8x^2 - 50\\)? \\(2(x + 5)(x …

Question

what is the completely factored form of \\(8x^2 - 50\\)?

\\(2(x + 5)(x - 5)\\)
\\(2(2x - 5)(2x - 5)\\)
\\(2(2x + 5)(2x + 5)\\)
\\(2(2x + 5)(2x - 5)\\)

Explanation:

Factor out the greatest common factor

$$ 8x^2 - 50 = 2(4x^2 - 25) $$

Factor the difference of squares

$$ 4x^2 - 25 = (2x)^2 - (5)^2 = (2x + 5)(2x - 5) $$

Combine the factors

$$ 8x^2 - 50 = 2(2x + 5)(2x - 5) $$

Answer:

  • \(2(x + 5)(x - 5)\)
  • \(2(2x - 5)(2x - 5)\)
  • \(2(2x + 5)(2x + 5)\)
  • \(2(2x + 5)(2x - 5)\) (Correct answer)