Question

what is the coefficient of the second term of the trinomial?
$(3x + 3)^2 = 9x^2 + bx + 9$
enter your answer in the box.
$b = \square$

Explanation:

Step1: Expand the left side

Use the formula \((a + b)^2 = a^2 + 2ab + b^2\), where \(a = 3x\) and \(b = 3\).
\((3x + 3)^2=(3x)^2+2\times(3x)\times3 + 3^2 = 9x^2+18x + 9\)

Step2: Compare with the right side

The right side is \(9x^2 + Bx + 9\). By comparing the coefficients of \(x\), we see that \(B = 18\).

Answer:

18