Question

1. what are the base units for the following?

a. mass \t\t\tkilograms (kg)
b. length \t\t\tmeters (m)
c. volume \t\t\tliter (l)
d. density \t\t\tgram/ cm³

convert the following:
a. 1 cm = 10 mm \t\t0.02 cm=.....0.2.....mm (multiply by 10)
b. 1 m = 1000 mm \t\t0.09 m =....90... mm (multiply by 1,000)
c. 1 cm = 1.0 10⁷ nm \t\t2.0 cm =.....2.0 10⁷... nm (multiply by 1.0 * 10⁷
d. 100 cm = 1m \t\t0.02 cm=....0.0002... m (divide by 100)

1. aluminum has a density of 2.40 g/cm³. what would be the mass of a sample whose volume is 10.0 cm³?

mass= density * volume
mass = 2.4 *10.0 = 24 grams

1. how many significant figures are in each of the following values?

a. 346572 \t\tall of these numbers are significant (1, 2, 3, 4, 5, 6, 7, 8, and 9 are always significant)
b. 9.2746419 \t\tall of these numbers are significant (1, 2, 3, 4, 5, 6, 7, 8, and 9 are always significant)
c. 0.00001 \t\tonly 1 is significant. if the number is smaller than 1, zeros between the decimal point and a whole number are not significant and zero before the decimal point is not significant.
d. 0.00826 \t\tonly 8,2 and 6 are significant

Explanation:

Step1: Identificar la fórmula

La fórmula para calcular la masa cuando se conoce la densidad y el volumen es \( \text{masa} = \text{densidad} \times \text{volumen} \).

Step2: Sustituir los valores

La densidad del aluminio es \( 2.40 \, \text{g/cm}^3 \) y el volumen de la muestra es \( 10.0 \, \text{cm}^3 \). Sustituimos estos valores en la fórmula: \( \text{masa} = 2.40 \, \text{g/cm}^3 \times 10.0 \, \text{cm}^3 \).

Step3: Realizar la operación

Multiplicamos \( 2.40 \) por \( 10.0 \). \( 2.40 \times 10.0 = 24.0 \) (teniendo en cuenta las cifras significativas, pero en el problema se muestra como 24 gramos, lo cual es una simplificación).

Answer:

La masa de la muestra de aluminio es 24 gramos (o 24.0 gramos si se consideran las cifras significativas).