Question

what is the axis of symmetry of the function y = - 3(x - 2)^2+1? a. x = 2 b. x=-2 c. x = 1 d. x = - 1

Explanation:

Step1: Recall formula for axis of symmetry of a parabola

For a quadratic function in vertex - form $y = a(x - h)^2+k$, the axis of symmetry is given by the equation $x = h$.

Step2: Identify values of $h$ in the given function

The given function is $y=-3(x - 2)^2+1$, where $h = 2$. So the axis of symmetry is $x = 2$.

Answer:

The axis of symmetry is $x = 2$.