Question

what is the axis of symmetry for the following function y=-4x²+3

Explanation:

Step1: Recall axis of symmetry formula

For quadratic $y=ax^2+bx+c$, axis is $x=-\frac{b}{2a}$

Step2: Identify coefficients

From $y=-4x^2+3$, $a=-4$, $b=0$

Step3: Calculate axis of symmetry

$x=-\frac{0}{2(-4)}=0$

Answer:

$x=0$