Question

1. what is the 109th term of the arithmetic sequence \\(963, 936, 909, 882, \dots\\)?

\\(a_{109} = -1,953\\)

\\(a_{109} = -1,980\\)

\\(a_{109} = -2,674\\)

\\(a_{109} = -3,879\\)

Explanation:

⚡ Using what you learned: Arithmetic Sequences

Step 1: Identify sequence parameters

$$ a_1 = 963 $$

$$ d = 936 - 963 = -27 $$

$$ n = 109 $$

Step 2: Apply the general term formula

$$ a_n = a_1 + (n - 1)d $$

$$ a_{109} = 963 + (109 - 1)(-27) $$

$$ a_{109} = 963 + 108(-27) $$

$$ a_{109} = 963 - 2916 $$

$$ a_{109} = -1953 $$

Answer:

\( a_{109} = -1,953 \)