Question

a weightlifter is holding a 200-kg barbell at a height of 1 meter above the ground. how much work is he performing while holding the barbell still? ______ joules

Explanation:

Step1: Recall Work Formula

Work \( W \) is calculated as \( W = F \cdot d \cdot \cos(\theta) \), where \( F \) is force, \( d \) is displacement, and \( \theta \) is the angle between force and displacement.

Step2: Analyze Displacement

The barbell is held still, so displacement \( d = 0 \) meters.

Step3: Calculate Work

Substitute \( d = 0 \) into the formula: \( W = F \cdot 0 \cdot \cos(\theta) = 0 \).

Answer:

0