Question

weeklyquiz - 11 5.6 - 5.7: problem 2
(1 point)
square the binomial: $(2x - 3y)^2$
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Explanation:

Step1: Use the formula \((a - b)^2=a^2-2ab + b^2\)

Here \(a = 2x\) and \(b=3y\). So \((2x-3y)^2=(2x)^2-2\times(2x)\times(3y)+(3y)^2\)

Step2: Calculate each term

\((2x)^2 = 4x^2\), \(2\times(2x)\times(3y)=12xy\), \((3y)^2 = 9y^2\)

Step3: Combine the terms

\((2x - 3y)^2=4x^2-12xy + 9y^2\)

Answer:

\(4x^2-12xy + 9y^2\)