Question

we want to find out how many grams of oxygen gas (o₂) are needed to completely react with 9.30 moles of aluminum.
4al + 3o₂ → 2al₂o₃
what is the given in the problem?
4 mol al
9.30 mol al
grams o₂

Explanation:

Step1: Analyze the problem statement

The problem asks for the given quantity. The problem states "how many grams of oxygen gas ($O_2$) are needed to completely react with 9.30 moles of aluminum". The chemical equation is $4Al + 3O_2
ightarrow2Al_2O_3$.

Step2: Identify the given

The given is the amount of aluminum. Among the options, 4 mol Al is from the balanced chemical equation (stoichiometric coefficient), grams $O_2$ is what we need to find (the unknown). The 9.30 mol Al is the given amount of the reactant (aluminum) provided in the problem statement.

Answer:

9.30 mol Al