Question

and we check the value of (f) at the right endpoint of the interval (0,2):

(f(\square) = \square)

the intermediate value theorem guarantees a solution to (f(x) = 1) in the interval ((0,2)) because

(f(\square) \le \square \le f(\square)).

Explanation:

Step1: Find the right endpoint value

$$f(2) = 2$$

Step2: Apply Intermediate Value Theorem

$$f(0) \le 1 \le f(2)$$

Answer:

\(f(2) = 2\)

\(f(0) \le 1 \le f(2)\)