Question

wave 1
wave 2
assuming the waves are traveling at the same speed, compare the waves.
the amplitude is
the wavelength is
the frequency is

Explanation:

Step1: Analyze amplitude

Amplitude is the maximum displacement from the rest position. Visually, both waves have the same height of displacement. So, amplitude is equal for both.

Step2: Analyze wavelength

Wavelength is the distance between two consecutive crests (or troughs). Wave 1 has larger gaps between crests compared to Wave 2. So, wavelength is greater for Wave 1.

Step3: Analyze frequency

Frequency is the number of waves passing a point per unit time. Since Wave 2 has more waves in the same length (shorter wavelength) and speed \(v = f\lambda\) (with \(v\) same), \(f=\frac{v}{\lambda}\). Smaller \(\lambda\) (Wave 2) gives higher \(f\). So, frequency is greater for Wave 2.

Answer:

The amplitude is equal for both waves.
The wavelength is greater for Wave 1.
The frequency is greater for Wave 2.