volume of each unknown #(1 or 2) ______ size of acid sample = 10.0ml
data table: volume of compound #______ used to titrate the unknown sample of acid

| | trial 1 | trial 2 | trial 3 |
| :--- | :--- | :--- | :--- |
| initial standard burette reading (ml) | 10.5 | 12.8 | 14.8 |
| final standard burette reading (ml) | 12.8 | 14.8 | 16.7 |
| volume of standard used (ml) | 2.3 | 2.00 | 1.9 |

1. calculate the average volume of compound # 1 standard solution added.
______ ml
______ l

2. use the ratio in part 4, calculate the concentration (m) of the 10.0 ml unknown acid.

3. using the molarity in question #2 above, of the 10.0 ml unknown acid, calculate the grams of the unknown acid in the sample.
$m = \frac{\text{mol}}{\text{l}}$

Question

volume of each unknown #(1 or 2) ______ size of acid sample = 10.0ml
data table: volume of compound #______ used to titrate the unknown sample of acid

| | trial 1 | trial 2 | trial 3 |
| :--- | :--- | :--- | :--- |
| initial standard burette reading (ml) | 10.5 | 12.8 | 14.8 |
| final standard burette reading (ml) | 12.8 | 14.8 | 16.7 |
| volume of standard used (ml) | 2.3 | 2.00 | 1.9 |

1. calculate the average volume of compound # 1 standard solution added.
______ ml
______ l

2. use the ratio in part 4, calculate the concentration (m) of the 10.0 ml unknown acid.

3. using the molarity in question #2 above, of the 10.0 ml unknown acid, calculate the grams of the unknown acid in the sample.
$m = \frac{\text{mol}}{\text{l}}$

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Titration Calculations" ], "new_concepts": [ "Burette Volume Calculation", "Average Volume Calculation" ], "current_concepts": [ "Titration Calculations", "Burette Volume Calculation", "Average Volume Calculation" ] } ## Identify the trial volumes Using the *Titration Calculations* knowledge point $$ \begin{aligned} &V_1 = 12.8\text{ mL} - 10.5\text{ mL} = 2.3\text{ mL}\ &V_2 = 14.8\text{ mL} - 12.8\text{ mL} = 2.00\text{ mL}\ &V_3 = 16.7\text{ mL} - 14.8\text{ mL} = 1.9\text{ mL} \end{aligned} $$ ## Calculate the average volume in mL Using the *Titration Calculations* knowledge point $$ \begin{aligned} V_{\text{avg}} &= \frac{2.3\text{ mL} + 2.00\text{ mL} + 1.9\text{ mL}}{3}\ V_{\text{avg}} &= \frac{6.2\text{ mL}}{3} \approx 2.07\text{ mL} \end{aligned} $$ ## Convert the average volume to liters Using the *Titration Calculations* knowledge point $$ \begin{aligned} V_{\text{avg, L}} &= \frac{2.07\text{ mL}}{1000}\ V_{\text{avg, L}} &\approx 0.00207\text{ L} \end{aligned} $$ 1. Calculate the average volume of compound # 1 standard solution added. 2.07 mL 0.00207 L { "subject": "Natural Science", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Natural Science", "Chemistry", "Titration Calculations" ] }

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QUESTION IMAGE

Question

Explanation:

Identify the trial volumes

Calculate the average volume in mL

Convert the average volume to liters

Answer:

	trial 1	trial 2	trial 3
final standard burette reading (ml)	12.8	14.8	16.7
volume of standard used (ml)	2.3	2.00	1.9