Question

the volume of a container expands when it is heated from 159 k to 456 k. what was the original volume if the final volume is 15.5 l?
v = ? l
assume that the number of moles and the pressure remain constant.

Explanation:

Step1: Apply Charles's Law

$\frac{V_1}{T_1} = \frac{V_2}{T_2}$
Here, $V_1$ = original volume, $T_1$ = 159 K, $V_2$ = 15.5 L, $T_2$ = 456 K. Rearrange to solve for $V_1$:
$V_1 = V_2 \times \frac{T_1}{T_2}$

Step2: Substitute values

$V_1 = 15.5\ \text{L} \times \frac{159\ \text{K}}{456\ \text{K}}$

Step3: Calculate the result

$V_1 = 15.5 \times \frac{159}{456} \approx 5.38\ \text{L}$

Answer:

5.38 L