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Question
verifying a triangle is a right triangle
for the given triangle, the slope of \\( \overline{zx} \\) is \\( \frac{1}{3} \\), the slope of
\\( \overline{zy} \\) is \\( \frac{-1}{2} \\), and the slope of \\( \overline{xy} \\) is 2. which statement
verifies that triangle xyz is a right triangle?
the slopes of \\( \overline{zx} \\) and \\( \overline{zy} \\) are opposite reciprocals.
the slopes of \\( \overline{xy} \\) and \\( \overline{zy} \\) are opposite reciprocals.
the slopes of \\( \overline{zx} \\) and \\( \overline{zy} \\) have opposite signs.
the slopes of \\( \overline{xy} \\) and \\( \overline{zy} \\) have opposite signs.
To determine if a triangle is a right triangle, we check if two sides are perpendicular. Two lines are perpendicular if their slopes are opposite reciprocals (product is -1).
- Slope of \( \overline{XY} \) is \( 2 \), slope of \( \overline{ZY} \) is \( \frac{-1}{2} \).
- Product of \( 2 \) and \( \frac{-1}{2} \) is \( 2\times\frac{-1}{2}=-1 \), so they are opposite reciprocals, meaning \( \overline{XY} \) and \( \overline{ZY} \) are perpendicular.
- Other options: Slopes of \( \overline{ZX} \) (\( \frac{1}{3} \)) and \( \overline{ZY} \) (\( \frac{-1}{2} \)): product \( \frac{1}{3}\times\frac{-1}{2}=\frac{-1}{6}
eq -1 \), so not opposite reciprocals. Opposite signs alone don't imply perpendicularity.
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The slopes of \( \overline{XY} \) and \( \overline{ZY} \) are opposite reciprocals.