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using trig to find a side question solve for x. round to the nearest te…

Question

using trig to find a side
question
solve for x. round to the nearest tenth, if
necessary.
answer
attempt 1 out of 3
x = submit answer

Explanation:

Step1: Identify the trigonometric ratio

In a right - triangle, \(\tan\theta=\frac{\text{opposite}}{\text{adjacent}}\). Here, \(\theta = 23^{\circ}\), the opposite side to \(\theta\) is \(MN = 7.4\) and the adjacent side is \(ML=x\). So, \(\tan(23^{\circ})=\frac{MN}{ML}\).

Step2: Substitute the values and solve for \(x\)

We know that \(\tan(23^{\circ})\approx0.4245\) and \(MN = 7.4\). From \(\tan(23^{\circ})=\frac{7.4}{x}\), we can rewrite it as \(x=\frac{7.4}{\tan(23^{\circ})}\).
Substitute \(\tan(23^{\circ})\approx0.4245\) into the formula: \(x=\frac{7.4}{0.4245}\).
\(x\approx17.4\)

Answer:

\(x = 17.4\)