Question

1. using a scale of 1 cm = 5 n, draw force vectors representing a +20 n force and a -10 n force.

Explanation:

Step1: Calculate the length of the vector for \(+ 20N\) force

Given the scale \(1cm = 5N\). Let \(x\) be the length of the vector for \(F = + 20N\). Using the proportion \(\frac{x}{F}=\frac{1cm}{5N}\), we have \(x=\frac{20N\times1cm}{5N}\)

$$x = 4cm$$

Draw a vector of length \(4cm\) in the positive direction (say, to the right).

Step2: Calculate the length of the vector for \(-10N\) force

Let \(y\) be the length of the vector for \(F=-10N\). Using the proportion \(\frac{y}{|F|}=\frac{1cm}{5N}\), we have \(y = \frac{10N\times1cm}{5N}\)

$$y=2cm$$

Draw a vector of length \(2cm\) in the negative direction (opposite to the positive direction, say, to the left).

Answer:

Draw a \(4cm\) vector in the positive direction and a \(2cm\) vector in the negative direction according to the scale \(1cm = 5N\).