Question

using the
as\ idea, how many bonds are made in the compound sicl4?
n = 40, a = 32, s = 8
16 8 4

Explanation:

Step1: Recall the formula for number of bonds

The formula using NAS idea is \(\frac{N - A - S}{2}\).

Step2: Substitute the values

Substitute \(N = 40\), \(A=32\), \(S = 8\) into the formula: \(\frac{40-32 - 8}{2}\).
First, calculate the numerator: \(40-32-8=0\). Then \(\frac{0}{2}=0\) (This is wrong approach, actually in NAS method for bonding (for octet - rule based compounds) \(N\) is total number of electrons in octets ( \(N=8\times\) (number of atoms) ), \(A\) is total number of valence electrons, \(S\) is number of non - bonding electrons.

Another way: In \(SiCl_{4}\), \(Si\) has \(4\) valence electrons and each \(Cl\) has \(7\) valence electrons. Total valence electrons \(A=(4)+4\times7 = 32\). Total electrons in octets \(N=(1 + 4)\times8=40\) (1 \(Si\) and 4 \(Cl\) atoms). Number of bonding electrons \(=N - A=40 - 32=8\). Since each bond has \(2\) electrons, number of bonds \(\frac{8}{2}=4\)

Answer:

4