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using circle c, find the measure of each arc or angle named. next to ea…

Question

using circle c, find the measure of each arc or angle named. next to each measure, write the name of the arc or angle. ed is a diameter.

m∠fcd = 60°
central angle
mae = 45°

madf = 135 + 60 = 195

mad = 135

m∠acd = 195

m∠acf = 120

mafd =

mfde =

Explanation:

Step1: Identify the measure of arc \(AE\)

The measure of arc \(AE\) is given as \(45^{\circ}\) (central angle theorem: the measure of an arc is equal to the measure of its central angle).

Step2: Calculate \(m\overset{\frown}{ADF}\)

\(m\overset{\frown}{ADF}=m\overset{\frown}{AD}+m\overset{\frown}{DF}\). Since \(m\overset{\frown}{AD} = 135^{\circ}\) (central angle \( \angle ACD=135^{\circ}\)) and \(m\overset{\frown}{DF}=60^{\circ}\) (central angle \( \angle FCD = 60^{\circ}\)), then \(m\overset{\frown}{ADF}=135^{\circ}+60^{\circ}=195^{\circ}\)

Step3: Calculate \(m\overset{\frown}{AD}\)

The central angle \( \angle ACD = 135^{\circ}\), so by the central angle theorem \(m\overset{\frown}{AD}=135^{\circ}\)

Step4: Calculate \(m\angle ACD\)

Given from the diagram, \(m\angle ACD = 135^{\circ}\) (central angle)

Step5: Calculate \(m\angle ACF\)

\(m\angle ACF=m\angle ACD + m\angle FCD\). Substituting \(m\angle ACD = 135^{\circ}\) and \(m\angle FCD=60^{\circ}\), we get \(m\angle ACF=135^{\circ}+60^{\circ}=195^{\circ}\)

Step6: Calculate \(m\overset{\frown}{AFD}\)

\(m\overset{\frown}{AFD}=m\overset{\frown}{AF}+m\overset{\frown}{FD}\). \(m\overset{\frown}{AF}=360^{\circ}-(45^{\circ}+120^{\circ}+60^{\circ}+135^{\circ})= 360^{\circ}-360^{\circ}+m\overset{\frown}{AF}\). Another way: \(m\overset{\frown}{AFD}=m\angle ACF\) (central angle - arc relationship). Since \(m\angle ACF = 195^{\circ}\), \(m\overset{\frown}{AFD}=195^{\circ}\)

Step7: Calculate \(m\overset{\frown}{FDE}\)

\(m\overset{\frown}{FDE}=m\overset{\frown}{FD}+m\overset{\frown}{DE}\). \(m\overset{\frown}{FD} = 60^{\circ}\), \(m\overset{\frown}{DE}=180^{\circ}-45^{\circ}=135^{\circ}\). So \(m\overset{\frown}{FDE}=60^{\circ}+135^{\circ}=195^{\circ}\)

Answer:

\(m\overset{\frown}{AE} = 45^{\circ}\), arc \(AE\)
\(m\overset{\frown}{ADF}=195^{\circ}\), arc \(ADF\)
\(m\overset{\frown}{AD}=135^{\circ}\), arc \(AD\)
\(m\angle ACD = 135^{\circ}\), \(\angle ACD\)
\(m\angle ACF=195^{\circ}\), \(\angle ACF\)
\(m\overset{\frown}{AFD}=195^{\circ}\), arc \(AFD\)
\(m\overset{\frown}{FDE}=195^{\circ}\), arc \(FDE\)