Question

use the venn diagram to calculate conditional probabilities. which conditional probabilities are correct? check all that apply. $p(d|f)=\frac{6}{34}$ $p(e|d)=\frac{7}{25}$ $p(d|e)=\frac{7}{25}$ $p(f|e)=\frac{8}{18}$ $p(e|f)=\frac{13}{21}$

Explanation:

Step1: Recall conditional - probability formula

The formula for conditional probability is $P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{n(A\cap B)}{n(B)}$, where $n(A\cap B)$ is the number of elements in the intersection of $A$ and $B$, and $n(B)$ is the number of elements in $B$.

Step2: Calculate $P(D|F)$

$n(D\cap F)=7 + 1=8$, $n(F)=7 + 1+21 + 5=34$, so $P(D|F)=\frac{8}{34}=\frac{4}{17}
eq\frac{6}{34}$.

Step3: Calculate $P(E|D)$

$n(E\cap D)=6 + 1=7$, $n(D)=13 + 6+1 + 5=25$, so $P(E|D)=\frac{7}{25}$.

Step4: Calculate $P(D|E)$

$n(D\cap E)=6 + 1=7$, $n(E)=4 + 6+1 + 7=18$, so $P(D|E)=\frac{7}{18}
eq\frac{7}{25}$.

Step5: Calculate $P(F|E)$

$n(F\cap E)=7 + 1=8$, $n(E)=4 + 6+1 + 7=18$, so $P(F|E)=\frac{8}{18}=\frac{4}{9}$.

Step6: Calculate $P(E|F)$

$n(E\cap F)=7 + 1=8$, $n(F)=7 + 1+21 + 5=34$, so $P(E|F)=\frac{8}{34}=\frac{4}{17}
eq\frac{13}{21}$.

Answer:

$P(E|D)=\frac{7}{25}$