QUESTION IMAGE
Question
use the table of electronegativities, above, to determine which type of bond should be formed between the two atoms.
- phosphorus silicon
- cobalt bromine
- germanium selenium
- silicon fluorine
- potassium nitrogen
- cesium oxide
- hydrogen phosphorus
- arsenic chloride
- lithium chloride
- iron carbon
Step1: Find electronegativity values
From the table:
- Phosphorus ($P$) has electronegativity $2.1$, Silicon ($Si$) has $1.8$.
- Cobalt ($Co$) has $1.9$, Bromine ($Br$) has $3.0$.
- Germanium ($Ge$) has $1.8$, Selenium ($Se$) has $2.5$.
- Silicon ($Si$) has $1.8$, Fluorine ($F$) has $4.0$.
- Potassium ($K$) has $0.8$, Nitrogen ($N$) has $3.0$.
- Cesium ($Cs$) has $0.7$, Oxygen ($O$) has $3.5$.
- Hydrogen ($H$) has $2.1$, Phosphorus ($P$) has $2.1$.
- Arsenic ($As$) has $2.1$, Chlorine ($Cl$) has $3.0$.
- Lithium ($Li$) has $1.0$, Chlorine ($Cl$) has $3.0$.
- Iron ($Fe$) has $1.8$, Carbon ($C$) has $2.5$.
Step2: Calculate electronegativity differences
- For $P$ and $Si$: $|2.1 - 1.8|=0.3$.
- For $Co$ and $Br$: $|3.0 - 1.9| = 1.1$.
- For $Ge$ and $Se$: $|2.5 - 1.8|=0.7$.
- For $Si$ and $F$: $|4.0 - 1.8|=2.2$.
- For $K$ and $N$: $|3.0 - 0.8|=2.2$.
- For $Cs$ and $O$: $|3.5 - 0.7|=2.8$.
- For $H$ and $P$: $|2.1 - 2.1|=0$.
- For $As$ and $Cl$: $|3.0 - 2.1|=0.9$.
- For $Li$ and $Cl$: $|3.0 - 1.0|=2.0$.
- For $Fe$ and $C$: $|2.5 - 1.8|=0.7$.
Step3: Determine bond type
- If $\Delta EN=0$: non - polar covalent.
- If $0\lt\Delta EN\lt1.7$: polar covalent.
- If $\Delta EN\geq1.7$: ionic.
- $P$ and $Si$: $\Delta EN = 0.3$, polar.
- $Co$ and $Br$: $\Delta EN=1.1$, polar.
- $Ge$ and $Se$: $\Delta EN = 0.7$, polar.
- $Si$ and $F$: $\Delta EN=2.2$, ionic.
- $K$ and $N$: $\Delta EN=2.2$, ionic.
- $Cs$ and $O$: $\Delta EN=2.8$, ionic.
- $H$ and $P$: $\Delta EN = 0$, non - polar covalent.
- $As$ and $Cl$: $\Delta EN=0.9$, polar.
- $Li$ and $Cl$: $\Delta EN=2.0$, ionic.
- $Fe$ and $C$: $\Delta EN = 0.7$, polar.
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| Atom 1 | Atom 2 | Electronegativity Difference Value | Bond Type |
|---|---|---|---|
| Cobalt | Bromine | $1.1$ | Polar |
| Germanium | Selenium | $0.7$ | Polar |
| Silicon | Fluorine | $2.2$ | Ionic |
| Potassium | Nitrogen | $2.2$ | Ionic |
| Cesium | Oxide | $2.8$ | Ionic |
| Hydrogen | Phosphorus | $0$ | Non - polar Covalent |
| Arsenic | Chloride | $0.9$ | Polar |
| Lithium | Chloride | $2.0$ | Ionic |
| Iron | Carbon | $0.7$ | Polar |