Question

1. use structure mr. wells drew a plan for a rectangular dog run. the vertices are \\(\left(2\frac{1}{3}, 7\frac{1}{2}\

ight)\\), \\((12, 7\frac{1}{2})\\), \\((12, 1)\\), and \\(\left(2\frac{1}{3}, 1\
ight)\\). what is the perimeter of the dog run?

Explanation:

Step1: Identify length and width

The rectangle has vertices $(2\frac{1}{3}, \frac{1}{2})$, $(12, \frac{1}{2})$, $(12, 1)$, $(2\frac{1}{3}, 1)$. Convert $2\frac{1}{3}$ to $\frac{7}{3} \approx 2.333$. Length $l = 12 - \frac{7}{3} = \frac{36 - 7}{3} = \frac{29}{3}$. Width $w = 1 - \frac{1}{2} = \frac{1}{2}$.

Step2: Calculate perimeter

Perimeter formula: $P = 2(l + w)$. Substitute values: $P = 2(\frac{29}{3} + \frac{1}{2}) = 2(\frac{58 + 3}{6}) = 2(\frac{61}{6}) = \frac{61}{3} = 20\frac{1}{3}$.

Answer:

$\frac{61}{3}$ (or $20\frac{1}{3}$)