Question

use the partial quotients method to find 748 ÷ 17. fill in the missing numbers.

Explanation:

Step1: Divide 748 by 17

We start by subtracting multiples of 17 from 748.

Step2: First multiple of 17

$170 = 10\times17$. Subtracting 170 from 748 gives $748 - 170=578$.

Step3: Second multiple of 17

Subtracting another 170 ($10\times17$) from 578 gives $578 - 170 = 408$.

Step4: Third multiple of 17

Subtracting 170 ($10\times17$) from 408 gives $408-170 = 238$.

Step5: Fourth multiple of 17

Subtracting 170 ($10\times17$) from 238 gives $238 - 170=68$.

Step6: Fifth multiple of 17

$68 = 4\times17$.

The sum of the partial - quotients is $10 + 10+10 + 10+4=44$ and the remainder is 0.

Answer:

The quotient is 44 and the remainder is 0. The filled - in numbers:
The first quotient digit is 44, remainder is 0.
The numbers multiplying 17 are 10, 10, 10, 10, 4 in order. And the intermediate results of subtraction are 578, 408, 238, 68, 0.