Question

use the partial quotients method to find 628 ÷ 55. fill in the missing numbers.

Explanation:

Step1: Find first partial - quotient

We know that $55\times10 = 550$. So the first partial - quotient is 10.
$628-550 = 78$.

Step2: Find second partial - quotient

Since $55\times1=55$, and $78 - 55=23$.
The total quotient is the sum of the partial - quotients $10 + 1=11$, and the remainder is 23.

Answer:

The quotient is 11 and the remainder is 23. In the long - division form:
The top - left box is 11, the top - right box (remainder) is 23, the box next to the arrow for $550$ is 10, the box below $550$ is 78, the box next to the arrow for 55 is 1, and the bottom box is 23.