Question

use the graph above to answer the following questions.
a.) what total distance did the object travel?

m
b.) when was the velocity positive?
from s to s
c.) what was the velocity at 8 s?
m/s

Explanation:

Step1: Calculate total distance

Total distance is the sum of all segments. From - 200m to 300m (distance \(300 - (-200)=500m\)), then stay (distance \(0m\)), then from 300m to 0m (distance \(300m\)). Total \(500 + 300=800m\).

Step2: Determine positive - velocity time

Velocity is positive when position is increasing. From \(0s\) to \(20s\).

Step3: Calculate velocity at \(8s\)

Velocity \(v=\frac{\Delta x}{\Delta t}\). At \(t = 0s,x=-200m\); at \(t = 10s,x = 0m\). \(v=\frac{0 - (-200)}{10}=20m/s\) (constant in \(0 - 20s\) interval).

Answer:

A. \(800\) m
B. From \(0\) s to \(20\) s
C. \(20\) m/s