Question

use the expression above to calculate g using your data from procedures 1 and 2. do you expected to be any better than the values obtained in for upward or downward travel? why? use for box below for the calculations and explanations.
assume gsin(θ)=a_avg gsin(10)=a_avg
g(0.17)=\frac{1.71}{0.17}
g = 10.06

Explanation:

Step1: Use formula for g

$g = \frac{a_{\text{avg}}}{\sin\theta}$

Step2: Substitute values

$a_{\text{avg}} = 1.71$, $\sin\theta \approx 0.17$

Step3: Calculate g

$g = \frac{1.71}{0.17} \approx 10.06$

Step4: Explain accuracy

Averaging reduces friction error, better than single direction.

Answer:

$g \approx 10.06$; The value is better because averaging reduces friction-related errors compared to upward/downward travel alone.