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the midsegment of a triangle is the base; or, the base of a triangle is the midsegment.
Step1: Recall the midsegment theorem
The midsegment theorem states that the midsegment of a triangle is parallel to the base and its length is half of the base length. So, the midsegment of a triangle is half of the base.
Step2: Use the relationship in reverse
If the midsegment \(m=\frac{1}{2}b\) (where \(m\) is the mid - segment and \(b\) is the base), then solving for \(b\) gives \(b = 2m\). So, the base of a triangle is twice the midsegment.
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The midsegment of a triangle is half of the base; OR, the base of a triangle is twice the midsegment.