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Question
use the diagram of a square pyramid to answer the question. what is the length of the slant height, l? a. 3 in. b. 9 in. c. √39 in. d. √41 in. e. √89 in.
Step1: Apply Pythagorean theorem
For a right - triangle, \(a^{2}+b^{2}=c^{2}\), where \(c\) is the hypotenuse. Here, one leg \(a = 5\) in and the other leg \(b\) is calculated as \(\frac{8}{2}=4\) in (since the base of the right - triangle formed is half of the side length of the square base of the pyramid). Let the slant height \(L\) be the hypotenuse.
Step2: Substitute values into the formula
Substitute \(a = 5\) and \(b = 4\) into \(a^{2}+b^{2}=L^{2}\). So, \(L^{2}=5^{2}+4^{2}\).
Step3: Solve for \(L\)
Take the square root of both sides. \(L=\sqrt{41}\) in.
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D. \(\sqrt{41}\) in.