Question

use this data table to calculate the amount of nitrogen produced by each development option.

development options | natural vegetation | fertilizer from lawns | fertilizer from golf | roadways and paved areas | total nitrogen per year
--- | --- | --- | --- | --- | ---
eco-housing | 0.4 lbs of n x 210 acres = 84 | 5 lbs of n x 10 acres = 50 | 25 lbs of n x 0 acres = 0 | 19.5 lbs of n x 10 acres = 195 | 369
missions | 0.4 lbs of n x 15 acres = 6 | 5 lbs of n x 215 acres = 1075 | 25 lbs of n x 0 acres = 0 | 19.5 lbs of n x 20 acres = 390 | 1351
park | 0.4 lbs of n x 245 acres = 98 | 5 lbs of n x 0 acres = 0 | 25 lbs of n x 0 acres = 0 | 19.5 lbs of n x 5 acres = 97.5 | 165.5
hotel | 0.4 lbs of n x 15 acres = 6 | 5 lbs of n x 45 acres = 225 | 25 lbs of n x 160 acres = 4000 | 19.5 lbs of n x 30 acres = 585 | 4636

1. put the development options in order from most nitrogen per year to least nitrogen per year

a.
b.
c.
d.

1. which development option is most likely to cause artificial eutrophication?

a.

1. what is the purpose of the calculations you did today?

a.

Explanation:

Question 1

Step1: Identify total nitrogen values

From the table, the total nitrogen per year for each development option is:

• Eco - homes: 369
• Mansions: 1351
• Park: 165.5
• Hotel: 4636

Step2: Order from most to least

Compare the values: \(4636>1351 > 369>165.5\)

Artificial eutrophication is caused by excessive nutrients (like nitrogen) entering water bodies. The development option with the highest total nitrogen per year is most likely to cause it. From the table, Hotel has the highest total nitrogen (4636 lbs per year).

The calculations were done to determine the amount of nitrogen produced by each development option. This helps in assessing the potential environmental impact (like eutrophication) of each development, as nitrogen is a key nutrient in eutrophication processes.

Answer:

a. Hotel
b. Mansions
c. Eco - homes
d. Park

Question 2