the units of the subway map below are in miles. suppose the routes between stations are straight. find the approximate distance a passenger would travel between stations j and k. the distance from station j to station k is approximately
(pound to the nearest tenth as needed.)

Question

Accepted Answer

# Explanation:
## Step1: Identify the coordinates of points J and K
Assume the coordinates of point J are $(x_1,y_1)$ and of point K are $(x_2,y_2)$. From the graph, if $J(- 6,1)$ and $K(2,-2)$
## Step2: Use the distance formula $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$
Substitute $x_1=-6,y_1 = 1,x_2=2,y_2=-2$ into the formula:
$$
\begin{align*}
d&=\sqrt{(2-(-6))^2+(-2 - 1)^2}\
&=\sqrt{(2 + 6)^2+(-3)^2}\
&=\sqrt{8^2+(-3)^2}\
&=\sqrt{64 + 9}\
&=\sqrt{73}
\end{align*}
$$
## Step3: Calculate the approximate value of $\sqrt{73}$
$\sqrt{73}\approx8.5$ (since $8^2=64$ and $9^2 = 81$, and $73$ is closer to $64$ than $81$, and using a calculator $\sqrt{73}\approx8.544\approx8.5$)

# Answer:
$8.5$

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QUESTION IMAGE

Question

Explanation:

Step1: Identify the coordinates of points J and K

Step2: Use the distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)

Step3: Calculate the approximate value of \(\sqrt{73}\)

Answer: