QUESTION IMAGE
Question
unit test #3
question 6 (1 point)
use the following information to answer the next question.
in a chemical activity performed by a group of students,
150 g of wood was combusted and the temperature of
the system changed from 27°c to 45°c. the specific
heat of wood is 1.26 j/g°c.
what is the amount of heat energy produced?
1104 j
1609 j
2492 j
3402 j
5103 j
Step1: Calculate the temperature change
The formula for temperature change is $\Delta T=T_{final}-T_{initial}$.
Given $T_{initial} = 27^{\circ}C$ and $T_{final}=45^{\circ}C$, so $\Delta T=45 - 27=18^{\circ}C$.
Step2: Use the heat - energy formula
The formula for heat energy is $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the temperature change.
Given $m = 150g$, $c=1.26J/g^{\circ}C$, and $\Delta T = 18^{\circ}C$.
Substitute the values into the formula: $Q=150\times1.26\times18$.
First, calculate $150\times1.26 = 189$.
Then, calculate $189\times18=(190 - 1)\times18=190\times18-1\times18=3420 - 18=3402J$.
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3402 J