Question

um ponto é escolhido aleatoriamente dentro do retângulo abaixo. qual é a probabilidade de que o ponto esteja dentro do triângulo? (a figura pode não estar desenhada em escala). 18 5 9 8 show your work here enter your answer check

Explanation:

Step1: Calculate rectangle area

The area formula for a rectangle is $A = l\times w$. Here, $l = 18$ and $w = 8$, so $A_{rectangle}=18\times8 = 144$.

Step2: Calculate triangle area

The area formula for a triangle is $A=\frac{1}{2}\times b\times h$. Here, $b = 9$ and $h = 5$, so $A_{triangle}=\frac{1}{2}\times9\times5=\frac{45}{2}= 22.5$.

Step3: Calculate probability

The probability $P$ that a randomly - chosen point in the rectangle is in the triangle is given by the ratio of the triangle's area to the rectangle's area. So $P=\frac{A_{triangle}}{A_{rectangle}}=\frac{22.5}{144}=\frac{225}{1440}=\frac{5}{32}$.

Answer:

$\frac{5}{32}$