Question

um ponto é escolhido aleatoriamente dentro do retângulo abaixo. qual é a probabilidade de que o ponto esteja dentro do triângulo? (a figura pode não estar desenhada em escala). 24 7 13 11 show your work here enter your answer check

Explanation:

Step1: Calculate rectangle area

The area formula for a rectangle is $A = l\times w$. Here, $l = 24$ and $w=11$, so $A_{rectangle}=24\times11 = 264$.

Step2: Calculate triangle area

The area formula for a triangle is $A=\frac{1}{2}\times b\times h$. Here, $b = 13$ and $h = 7$, so $A_{triangle}=\frac{1}{2}\times13\times7=\frac{91}{2}=45.5$.

Step3: Calculate probability

The probability $P$ that a randomly - chosen point in the rectangle is in the triangle is given by $P=\frac{A_{triangle}}{A_{rectangle}}$. So $P=\frac{45.5}{264}=\frac{91}{528}$.

Answer:

$\frac{91}{528}$