Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

type the correct answer in the box. use numerals instead of words. if n…

Question

type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar. what value of x satisfies this equation? 1.5(4)^{2x} = 12 round your answer to the nearest hundredth. the value of x is

Explanation:

Step1: Isolate the exponential term

Divide both sides of the equation \(1.5(4)^{2x}=12\) by \(1.5\).
\(\frac{1.5(4)^{2x}}{1.5}=\frac{12}{1.5}\)
Simplifying, we get \(4^{2x} = 8\).

Step2: Express both sides with the same base

We know that \(4 = 2^2\) and \(8=2^3\). Substitute these into the equation:
\((2^2)^{2x}=2^3\)
Using the exponent rule \((a^m)^n=a^{mn}\), we have \(2^{4x}=2^3\).

Step3: Solve for \(x\)

Since the bases are the same, we can set the exponents equal to each other:
\(4x = 3\)
Divide both sides by \(4\):
\(x=\frac{3}{4}= 0.75\) (Wait, let's check again. Wait, maybe I made a mistake in base conversion. Let's try another way.

Wait, going back to step 1: \(4^{2x}=8\). Let's take logarithms. Take the natural logarithm of both sides:
\(\ln(4^{2x})=\ln(8)\)
Using the logarithm power rule \(\ln(a^b)=b\ln(a)\), we get \(2x\ln(4)=\ln(8)\)
Then \(2x=\frac{\ln(8)}{\ln(4)}\)
Calculate \(\frac{\ln(8)}{\ln(4)}=\frac{3\ln(2)}{2\ln(2)}=\frac{3}{2} = 1.5\) (since \(\ln(8)=\ln(2^3)=3\ln(2)\) and \(\ln(4)=\ln(2^2)=2\ln(2)\))
Then \(2x = 1.5\)
So \(x=\frac{1.5}{2}=0.75\)? Wait, no, wait when we did \(4^{2x}=8\), let's check with original equation. Let's plug \(x = 0.75\) into \(1.5(4)^{2x}\):

\(2x=1.5\), \(4^{1.5}=4^{\frac{3}{2}}=\sqrt{4^3}=\sqrt{64} = 8\), then \(1.5\times8 = 12\), which matches. Wait, but earlier when I did base 2, I had a mistake. Wait, \(4^{2x}=8\), \(4^{2x}=2^{4x}\), \(8 = 2^3\), so \(2^{4x}=2^3\) implies \(4x = 3\) so \(x=\frac{3}{4}=0.75\). Yes, that's correct. Wait, but let's do it with common logarithm.

Alternative way:
From \(4^{2x}=8\), take log base 10:
\(2x\log(4)=\log(8)\)
\(2x=\frac{\log(8)}{\log(4)}\)
\(\log(8)\approx0.9031\), \(\log(4)\approx0.6021\)
\(\frac{0.9031}{0.6021}\approx1.5\)
\(2x = 1.5\)
\(x = 0.75\)

Wait, but let's check again. Wait, the original equation: \(1.5\times4^{2x}=12\). If \(x = 0.75\), \(2x = 1.5\), \(4^{1.5}=8\), \(1.5\times8 = 12\), which is correct. So the value of \(x\) is \(0.75\).

Wait, but maybe I made a mistake in the first base conversion. Let's see: \(4^{2x}=8\), \(4^{2x}=2^{4x}\), \(8 = 2^3\), so \(4x = 3\), so \(x=\frac{3}{4}=0.75\). Yes, that's correct.

Answer:

\(0.75\)