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two positive integers have a product of 176. one integer is 5 less than…

Question

two positive integers have a product of 176. one integer is 5 less than the other integer. which equation can be used to find the value of x, the greater integer?
○ $x^2 + 5 = 176$
○ $x(x + 5) = 176$
○ $x(x - 5) = 176$
○ $x^2 - 5 = 176$

Explanation:

Step1: Define the variables

Let \( x \) be the greater integer. Then the smaller integer is \( x - 5 \) (since one integer is 5 less than the other).

Step2: Set up the product equation

The product of the two integers is 176. So, we multiply the two integers: \( x \times (x - 5) = 176 \), which is \( x(x - 5)=176 \).

Answer:

C. \( x(x - 5) = 176 \) (assuming the options are labeled A, B, C, D with C being \( x(x - 5) = 176 \))