Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

try it! understand conditional probability 1. a student committee is be…

Question

try it! understand conditional probability

  1. a student committee is being formed to decide how after - school activities will be funded. the committee members are selected at random from current club members. the frequency table shows the current club membership data.

a. what is the probability that a member of the drama club is a sophomore, ( p(\text{sophomore}|\text{drama}) )?
b. what is the probability that a sophomore is a member of the drama club, ( p(\text{drama}|\text{sophomore}) )? is ( p(\text{sophomore}|\text{drama}) ) the same as ( p(\text{drama}|\text{sophomore}) )? explain

Explanation:

Step1: Recall the formula for conditional probability

The formula for conditional probability is \(P(A|B)=\frac{P(A\cap B)}{P(B)}\). In terms of frequency tables, \(P(A|B)=\frac{\text{Number of elements in }A\cap B}{\text{Number of elements in }B}\)

Step2: Solve for \(P(\text{sophomore}|\text{drama})\)

For \(P(\text{sophomore}|\text{drama})\), the number of elements in \(\text{sophomore}\cap\text{drama}\) is \(3\) (from the table). The number of elements in \(\text{drama}\) is \(17\) (total of the drama column). So \(P(\text{sophomore}|\text{drama})=\frac{3}{17}\)

Step3: Solve for \(P(\text{drama}|\text{sophomore})\)

For \(P(\text{drama}|\text{sophomore})\), the number of elements in \(\text{drama}\cap\text{sophomore}\) is \(3\). The number of elements in \(\text{sophomore}\) is \(36\) (total of the sophomore row). So \(P(\text{drama}|\text{sophomore})=\frac{3}{36}=\frac{1}{12}\)

Step4: Compare the two probabilities

Since \(\frac{3}{17}\approx0.176\) and \(\frac{1}{12}\approx0.083\), \(P(\text{sophomore}|\text{drama})
eq P(\text{drama}|\text{sophomore})\)

Answer:

a. \(\frac{3}{17}\)

b. \(P(\text{drama}|\text{sophomore})=\frac{3}{36}=\frac{1}{12}\). \(P(\text{sophomore}|\text{drama})\) is not the same as \(P(\text{drama}|\text{sophomore})\) because \(P(A|B)=\frac{n(A\cap B)}{n(B)}\) and \(P(B|A)=\frac{n(A\cap B)}{n(A)}\), and \(n(A)
eq n(B)\) (where \(A = \text{sophomore}\) and \(B=\text{drama}\))