Question

try again. use >, <, or = to make the statement true.
$2 \frac{1}{3} + 3 \frac{1}{5} \square 6 + \frac{7}{8}$
$=$ $>$ $<$

Explanation:

Step1: Convert mixed numbers to improper fractions

$2\frac{1}{3} = \frac{7}{3}$, $3\frac{1}{5} = \frac{16}{5}$

Step2: Calculate left-hand side sum

$\frac{7}{3} + \frac{16}{5} = \frac{35}{15} + \frac{48}{15} = \frac{83}{15} \approx 5.533$

Step3: Calculate right-hand side sum

$6 + \frac{7}{8} = \frac{48}{8} + \frac{7}{8} = \frac{55}{8} = 6.875$

Step4: Compare the two results

$5.533 < 6.875$

Answer:

$2\frac{1}{3} + 3\frac{1}{5} < 6 + \frac{7}{8}$