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Question
in triangle rst, ( mangle r>mangle s + mangle t ). which must be true of triangle rst? check all that apply.
( square mangle r>90^{circ} )
( square mangle s + mangle t<90^{circ} )
( square mangle s = mangle t )
( square mangle r>mangle t )
( square mangle r>mangle s )
( square mangle s>mangle t )
Step1: Recall triangle angle sum
In any triangle, the sum of interior angles is \(180^\circ\). So for \(\triangle RST\), \(m\angle R + m\angle S + m\angle T = 180^\circ\), which implies \(m\angle S + m\angle T = 180^\circ - m\angle R\).
Step2: Analyze \(m\angle R > m\angle S + m\angle T\)
Substitute \(m\angle S + m\angle T = 180^\circ - m\angle R\) into \(m\angle R > m\angle S + m\angle T\). We get \(m\angle R > 180^\circ - m\angle R\).
Step3: Solve for \(m\angle R\)
Add \(m\angle R\) to both sides: \(2m\angle R > 180^\circ\), then divide by 2: \(m\angle R > 90^\circ\). So the first option is true.
Step4: Analyze \(m\angle S + m\angle T\)
Since \(m\angle R > 90^\circ\) and \(m\angle R + m\angle S + m\angle T = 180^\circ\), then \(m\angle S + m\angle T = 180^\circ - m\angle R < 180^\circ - 90^\circ = 90^\circ\). So the second option is true.
Step5: Analyze \(m\angle R > m\angle T\) and \(m\angle R > m\angle S\)
We know \(m\angle R > m\angle S + m\angle T\). Since \(m\angle S\) and \(m\angle T\) are positive angles, \(m\angle R > m\angle S\) (because \(m\angle S + m\angle T > m\angle S\)) and \(m\angle R > m\angle T\) (because \(m\angle S + m\angle T > m\angle T\)). So the fourth and fifth options are true.
Step6: Analyze \(m\angle S = m\angle T\) and \(m\angle S > m\angle T\)
There's no information given to suggest \(m\angle S = m\angle T\) or \(m\angle S > m\angle T\). These depend on the specific triangle, not the given inequality \(m\angle R > m\angle S + m\angle T\). So these options are not necessarily true.
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- \(m\angle R > 90^\circ\)
- \(m\angle S + m\angle T < 90^\circ\)
- \(m\angle R > m\angle T\)
- \(m\angle R > m\angle S\)