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the triangle below is isosceles. find the length of side ( x ) to the n…

Question

the triangle below is isosceles. find the length of side ( x ) to the nearest tenth. answer attempt 1 out of 2 ( x= )

Explanation:

Step1: Apply Pythagorean theorem

Since it's an isosceles right - triangle, by Pythagorean theorem \(a^{2}+b^{2}=c^{2}\). Here \(a = b=x\) and \(c = 9\). So \(x^{2}+x^{2}=9^{2}\).

Step2: Simplify the equation

\(2x^{2}=81\). Then \(x^{2}=\frac{81}{2}=40.5\).

Step3: Solve for \(x\)

\(x=\sqrt{40.5}\approx6.4\)

Answer:

\(6.4\)