Question

if a translation of ( t_{-1,-8}(x,y) ) is applied to square abcd, what is the ( y ) coordinate of ( b )?
( \bigcirc - 12 )
( \bigcirc - 8 )
( \bigcirc - 6 )
( \bigcirc - 2 )

Explanation:

Step1: Find the original y - coordinate of point B

From the graph, the coordinates of point B are \((1,2)\). So the original \(y\) - coordinate of \(B\) is \(y = 2\).

Step2: Apply the translation rule for the \(y\) - coordinate

The translation rule is \(T_{-3,-8}(x,y)=(x - 3,y-8)\). For the \(y\) - coordinate, we use the formula \(y'=y - 8\).
Substitute \(y = 2\) into the formula: \(y'=2-8=-6\).

Answer:

-6