Question

a toy drone with a mass of 1.2 kg has a gpe of 117.6 j while hovering. what is its height above the ground?

Explanation:

Step1: Write the formula for gravitational potential energy (GPE)

The formula for GPE is \(GPE = mgh\), where \(m\) is the mass, \(g\) is the acceleration due to gravity (\(g = 9.8\ m/s^{2}\)), and \(h\) is the height.

Step2: Rearrange the formula to solve for \(h\)

We can rewrite the formula as \(h=\frac{GPE}{mg}\).

Step3: Substitute the given values into the formula

Given \(GPE = 117.6\ J\), \(m = 1.2\ kg\), and \(g = 9.8\ m/s^{2}\), we substitute these values: \(h=\frac{117.6}{1.2\times9.8}\).

Step4: Calculate the value of \(h\)

First, calculate \(1.2\times9.8 = 11.76\). Then, \(\frac{117.6}{11.76}=10\).

Answer:

The height of the toy drone above the ground is \(10\ m\).